Solved need help with custom elevon mixing

ezbruh

Active member
For people reading this who do not understand what math is happening, I’ll simplify. Left elevon = pitch - roll, right elevon = pitch + roll. Let’s say the roll value to the left is -1 and to the right it’s 1. Same goes for pitch; down is -1, up is 1. If you roll left and pitch is neutral, left goes up (0 + 1 = 1) and right goes down (0 - 1 = -1). Then if you also pitch up, the left elevon stays up as its new value of 2 gets clamped to 1 and the right elevon goes to 0. The over all effect is rolling left and pitching up. If you pitch down, left goes neutral and right stays down. If you pitch up with no roll, both are equal as it’s 1 - 0 and 1 + 0 for the left and right elevons respectively.