EraJomppa
RC Enthusiast
I´ll divide my question in 2 parts, but let me start by saying that I have some knowledge of the subject but making the logical conclusion is sometimes difficult so I want to get some suggestions and opinions from you guys.
1st.
I got two 6cell (6s) batteries connected in parallel under load. The other battery is older than the other, but are otherwise the same, 6s 4000mAh. When I charge them I notice that the older battery lost 1900mAh during load, and the new battery lost 2100mAh. Using only new batteries, both lose 2000mAh, so the consumption is same, but the capacity loss is distributed unevenly.
My logic is that the parallel batteries act as parallel resistors;
-Both batteries operate on the same voltage
-The current flowing through both batteries is I=U/R
-New battery loses more capacity thus more current flows thru it
-> This means that the new battery has lower internal resistance (doesn't it?)
Now this is actually disadvantageous to the new battery since it drains faster than the old one I guess. The system I'm using does have low voltage cut-off but still I'm worried that this strains the batteries unevenly. Is there a way to prevent this? I suppose calculating the difference in resistance inside the batteries and increasing the resistance of the new battery with a resistor?... I dont know if you can or if you should
2nd.
This is my configuration:
I got total of 9s1600mAh of batteries (~36V). Connected as seen in the picture: (2x 6s4000mAh in parallel) in series with (2x 3s4000mAh in parallel), those and in parallel with an identical set.
My question is that one of the 6s batteries is older than the other 6s batteries and causes the other 6s it is in parallel with to drain more rapidly in this current configuration; How can I improve my configuration in order to minimize this effect? would it be better if I had all the 6s batteries in parallel with each other and the in series with all the 3s batteries (that are also in parallel with each other)? Or rather make 4 pairs of 6s+3s batteries in series and parallel all of those (effectively 9s) sets with each other?
I feel that my current configuration is forcing all the strain into the one battery that gets paired with the old 6s. That is the question
__________
Just ranting here, since someone might wonder why all these batteries...
I am using these batteries in my electric bicycle with 500W motor. It does not create huge currents (compared to my 2kW plane that flies with just one 6s4000mAh) and I get away with smaller diameter wires in the connections.
I also use these same batteries with my 200% Dusty, but right now I use the bicycle daily and they see their primary use there.
Here is my charging case that fits neatly into my bicycle saddle-pack if I need to charge batteries on the road.
The legal limit of power in electric bikes in Finland is 250W so I dont really use the 500W setting, also the speed is limited to 25km/h (if you go faster the motor wont be helping you along). I got roughly 575Wh (=36V*16Ah) of batteries so if I use the allowed 250W of motor assistance and go 25km/h I get 2h 20min of riding, which at 25km/h is 57.5km. This is the theoretical minimum I should get. But when you ride you dont allways use all the 250W and in the uphill you might use more (I can if I want since it's 500W motor). Also I never drain my batteries fully. Thus my range is somewhere around 50-70km, or even more if I feel frisky and use smaller level of assistance. Thanks for reading
1st.
I got two 6cell (6s) batteries connected in parallel under load. The other battery is older than the other, but are otherwise the same, 6s 4000mAh. When I charge them I notice that the older battery lost 1900mAh during load, and the new battery lost 2100mAh. Using only new batteries, both lose 2000mAh, so the consumption is same, but the capacity loss is distributed unevenly.
My logic is that the parallel batteries act as parallel resistors;
-Both batteries operate on the same voltage
-The current flowing through both batteries is I=U/R
-New battery loses more capacity thus more current flows thru it
-> This means that the new battery has lower internal resistance (doesn't it?)
Now this is actually disadvantageous to the new battery since it drains faster than the old one I guess. The system I'm using does have low voltage cut-off but still I'm worried that this strains the batteries unevenly. Is there a way to prevent this? I suppose calculating the difference in resistance inside the batteries and increasing the resistance of the new battery with a resistor?... I dont know if you can or if you should
2nd.
This is my configuration:
I got total of 9s1600mAh of batteries (~36V). Connected as seen in the picture: (2x 6s4000mAh in parallel) in series with (2x 3s4000mAh in parallel), those and in parallel with an identical set.
My question is that one of the 6s batteries is older than the other 6s batteries and causes the other 6s it is in parallel with to drain more rapidly in this current configuration; How can I improve my configuration in order to minimize this effect? would it be better if I had all the 6s batteries in parallel with each other and the in series with all the 3s batteries (that are also in parallel with each other)? Or rather make 4 pairs of 6s+3s batteries in series and parallel all of those (effectively 9s) sets with each other?
I feel that my current configuration is forcing all the strain into the one battery that gets paired with the old 6s. That is the question
__________
Just ranting here, since someone might wonder why all these batteries...
I am using these batteries in my electric bicycle with 500W motor. It does not create huge currents (compared to my 2kW plane that flies with just one 6s4000mAh) and I get away with smaller diameter wires in the connections.
I also use these same batteries with my 200% Dusty, but right now I use the bicycle daily and they see their primary use there.
Here is my charging case that fits neatly into my bicycle saddle-pack if I need to charge batteries on the road.
The legal limit of power in electric bikes in Finland is 250W so I dont really use the 500W setting, also the speed is limited to 25km/h (if you go faster the motor wont be helping you along). I got roughly 575Wh (=36V*16Ah) of batteries so if I use the allowed 250W of motor assistance and go 25km/h I get 2h 20min of riding, which at 25km/h is 57.5km. This is the theoretical minimum I should get. But when you ride you dont allways use all the 250W and in the uphill you might use more (I can if I want since it's 500W motor). Also I never drain my batteries fully. Thus my range is somewhere around 50-70km, or even more if I feel frisky and use smaller level of assistance. Thanks for reading